Problems on Ages · Question 28 · Hard
A is twice as old as B was when A was as old as B is now. If the sum of their present ages is 63 years, what is A's present age?
- 42 years
- 36 years
- 27 years
- 32 years
Answer and explanation
Answer: B. 36 years
Explanation: A was B's present age (A − B) years ago, when B was B − (A − B) = 2B − A. So A = 2(2B − A), i.e. 3A = 4B. With A + B = 63, A = 36 and B = 27.
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