Algebra & Equations · Question 10 · Medium
Algebra & Equations question 10
Five years ago, a father was seven times as old as his son. Five years from now, he will be three times as old as his son. What is the father's present age?
- 10 years
- 35 years
- 40 years
- 45 years
Answer and explanation
Answer: C. 40 years
Explanation: Let son = s, father = f. f − 5 = 7(s − 5) and f + 5 = 3(s + 5). Subtracting: 10 = 3s + 15 − 7s + 35, so 4s = 40, s = 10 and f = 40.
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