Number System · Question 14 · Hard
What is the smallest natural number which, when divided by 5, 6 and 8, leaves remainders 3, 4 and 6 respectively?
- 238
- 118
- 122
- 98
Answer and explanation
Answer: B. 118
Explanation: In each case the remainder is 2 less than the divisor, so the number is LCM(5, 6, 8) − 2 = 120 − 2 = 118.
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