Number System · Question 29 · Hard
What are the last two digits of 7^2026?
- 49
- 43
- 07
- 01
Answer and explanation
Answer: A. 49
Explanation: 7^4 = 2401 ends in 01, so powers of 7 repeat their last two digits every 4 steps. 2026 = 4 × 506 + 2, so the last two digits match 7^2 = 49.
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