Permutation & Combination · Question 15 · Hard
Permutation & Combination question 15
An exam has 5 questions in Section A and 5 in Section B. A student must answer 6 questions with at least 2 from each section. In how many ways can she choose?
- 250
- 200
- 210
- 100
Answer and explanation
Answer: B. 200
Explanation: Possible splits (A, B) are (2, 4), (3, 3), (4, 2): 10 × 5 + 10 × 10 + 5 × 10 = 50 + 100 + 50 = 200.
Previous: In how many arrangements of the letters of the word PENCIL are the two vowels… · Next: A locker code consists of 4 letters chosen from A, B, C, D, E and F, and…
Practise permutation & combination
Try a fresh set of permutation & combination questions with an explanation after every answer, free and without signing up: Permutation & Combination practice. Or sit a full placement mock test.
More permutation & combination questions
- In how many ways can 6 friends be seated around a round table (arrangements…
- How many 4-digit even numbers can be formed using the digits 0, 1, 2, 3, 4, 5…
- In how many arrangements of the letters of the word PENCIL are the two vowels…
- A locker code consists of 4 letters chosen from A, B, C, D, E and F, and…
- In a college cricket league, each of 10 teams plays every other team exactly…
- A canteen thali comes with any 2 different sabzis out of 5 and any 1 dal out…
- If nC2 = 36, what is the value of n?
- Three different prizes are to be given to 5 students, and any student may win…
- How many distinct arrangements can be made of the letters of the word BANANA?
- In how many arrangements of the letters of the word TABLE do the vowels occupy…
More quantitative aptitude practice
Probability · Data Interpretation · Mensuration · Algebra & Equations · Number System · HCF & LCM · Simplification · Percentages
LogicWiz Exams home · All practice topics · Placement mock tests · Daily 10 challenge