C Programming · Question 5 · Easy

What will be the output of the following C program?

#include <stdio.h>

int main(void) {
    int i;
    for (i = 0; i < 5; i++);
    printf("%d", i);
    return 0;
}
  1. 01234
  2. 5
  3. 4
  4. Compilation error
Answer and explanation

Answer: B. 5

Explanation: The semicolon right after the for header makes the loop body empty. The loop just runs i up to 5, then printf runs once and prints 5.

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