C Programming · Question 29 · Hard

What will be the output of the following C program?

#include <stdio.h>

void f(int n) {
    if (n <= 0)
        return;
    f(n - 2);
    printf("%d ", n);
    f(n - 3);
}

int main(void) {
    f(5);
    return 0;
}
  1. 1 2 3 5
  2. 5 3 1 2
  3. 1 3 2 5
  4. 1 3 5 2
Answer and explanation

Answer: D. 1 3 5 2

Explanation: f(5) first calls f(3), which calls f(1); f(1) prints 1, so f(3) then prints 3 (its f(0) call prints nothing). Back in f(5), 5 is printed, and then f(2) prints 2. The output is 1 3 5 2.

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