Cloud & DevOps · Question 30 · Hard
What does this shell command print?
false && echo A || echo B- A
- B
- A, then B on the next line
- Nothing
Answer and explanation
Answer: B. B
Explanation: false exits with a non-zero status, so the && part (echo A) is skipped. The || part runs because the preceding command failed, so only B is printed.
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