Object-Oriented Programming · Question 13 · Hard
What is the output of the following Java code?
static void change(StringBuilder sb) {
sb.append("World");
sb = new StringBuilder("New");
}
// in main:
StringBuilder s = new StringBuilder("Hello");
change(s);
System.out.println(s);- Hello
- New
- HelloWorld
- NewWorld
Answer and explanation
Answer: C. HelloWorld
Explanation: Java passes the object reference by value. append() changes the shared object, so it now holds "HelloWorld". Reassigning sb inside the method changes only the local copy of the reference, so s is unaffected.
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