Object-Oriented Programming · Question 21 · Medium
What is the output of the following C++ program?
#include <iostream>
using namespace std;
class Base {
public:
Base() { cout << "B "; }
~Base() { cout << "~B "; }
};
class Derived : public Base {
public:
Derived() { cout << "D "; }
~Derived() { cout << "~D "; }
};
int main() {
Derived d;
return 0;
}- D B ~B ~D
- B D ~B ~D
- D B ~D ~B
- B D ~D ~B
Answer and explanation
Answer: D. B D ~D ~B
Explanation: Constructors run from base to derived (B, then D). Destructors run in the reverse order when d goes out of scope (~D, then ~B).
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