Pseudo-code · Question 2 · Easy

What will be the output of the following pseudocode?

Integer x, y
Set x = 7, y = 3
if (x mod y > 0)
    x = x * y
else
    x = x + y
end if
Print x
  1. 21
  2. 10
  3. 7
  4. 1
Answer and explanation

Answer: A. 21

Explanation: 7 mod 3 = 1, which is greater than 0, so the if-branch runs and x = 7 × 3 = 21.

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