Pseudo-code · Question 27 · Hard

What will be the output of the following pseudocode? (Note: array indices start at 0 and for-loop bounds are inclusive.)

Integer arr[5] = {2, 4, 6, 8, 10}
Integer i
for (i = 0 to 3)
    arr[i + 1] = arr[i + 1] + arr[i]
end for
Print arr[4] - arr[2]
  1. 16
  2. 20
  3. 18
  4. 4
Answer and explanation

Answer: C. 18

Explanation: Each element adds the already-updated previous one, giving running totals [2, 6, 12, 20, 30]. So arr[4] - arr[2] = 30 - 12 = 18.

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