Computer Networks · Question 12 · Hard
Computer Networks question 12
In a stop-and-wait protocol, transmitting one frame takes 1 ms and the one-way propagation delay is 2 ms. Ignoring ACK transmission and processing time, what is the link utilisation (efficiency)?
- 33%
- 25%
- 20%
- 50%
Answer and explanation
Answer: C. 20%
Explanation: Efficiency = Tt / (Tt + 2 × Tp) = 1 / (1 + 4) = 0.2, or 20%. The sender is busy for 1 ms out of every 5 ms cycle.
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