Computer Networks · Question 30 · Hard
Computer Networks question 30
An IPv4 datagram of 4,000 bytes (20-byte header + 3,980 bytes of data) must cross a link with an MTU of 1,500 bytes. Each fragment carries a 20-byte header. What is the fragment-offset field value of the third fragment?
- 2960
- 370
- 296
- 740
Answer and explanation
Answer: B. 370
Explanation: Each fragment can carry 1,480 data bytes (a multiple of 8). The fragments carry 1,480, 1,480 and 1,020 bytes. The third starts at byte 2,960, and the offset is counted in 8-byte units: 2,960 / 8 = 370.
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