Permutation & Combination · Question 26 · Medium
In how many ways can 5 boys and 3 girls sit in a row so that no two girls sit next to each other?
- 2,880
- 14,400
- 4,320
- 720
Answer and explanation
Answer: B. 14,400
Explanation: Seat the boys first in 5! = 120 ways; this creates 6 gaps. Place the 3 girls in 3 of these gaps in 6P3 = 120 ways. Total = 120 × 120 = 14,400.
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