Permutation & Combination · Question 27 · Hard
How many 5-digit numbers divisible by 5 can be formed using the digits 0, 1, 2, 3, 4, 5 if no digit is repeated?
- 120
- 216
- 192
- 240
Answer and explanation
Answer: B. 216
Explanation: Ending in 0: the other four places use 5P4 = 120 ways. Ending in 5: the first digit cannot be 0, so 4 choices, then 4 × 3 × 2 for the middle: 96. Total = 120 + 96 = 216.
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