Computer Networks · Question 26 · Medium

Computer Networks question 26

The network 192.168.5.0/24 must be divided into equal-sized subnets, each with at least 50 usable host addresses. What is the maximum number of such subnets?

  1. 2
  2. 4
  3. 8
  4. 5
Answer and explanation

Answer: B. 4

Explanation: A /26 subnet has 2^6 - 2 = 62 usable hosts (enough), while /27 has only 30. Going from /24 to /26 borrows 2 bits, giving 2^2 = 4 subnets.

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